Find given number is Armstrong Number or not

Armstrong Number

 void main()
 {
     int n,b=0,t;
     clrscr();
     printf("Enter the no");
     scanf("%d",&n);
     t=n;
     while(n>0)
     {
             a=n%10;
             b=b+a*a*a;
             n=n/10;
     }
     if(b==t)
     {
             printf("Armstrong no");
     }
      else
     {
             printf("Not an armstrong no");
     }
     getch();
 }